While driving a 12-metre city bus I kept meeting rules without reasons. A manual says leave seven metres before you pull out; it does not say why seven. So I derived it. Take the bicycle model — one steered axle, one fixed axle, a wheelbase between them, no mass and no time — and the turn radius at full lock is a single line of trigonometry.
R = L / tan θ = 6.0 / tan 40° = 7.15 m
φ = arccos(1 − w / R) = 59.3°
x = R sin φ = 6.15 m → 6.5–7.0 m with a safety pad
That answer is exact, and it is exact because of everything it leaves out. There is no mass in it, no tire, no articulation, no time. It is a statement about shapes. The full derivation — clearance, the three-phase S-curve, and the straight segment between the two locks — is written up in the research archive.
Then I wanted to ask the questions the bicycle model cannot answer. What if the vehicle is not one body but three, hinged? What if the combination weighs 96 tonnes and the load’s centre of gravity is two metres up? What if the corner is taken at a speed, in a gear, with brakes that are already hot? Every one of those breaks the closed form. You can still get the number — you just have to integrate instead of solve. That is what the simulator is. The same trigonometry is still in it, line for line: the tractor’s steering box computes R = wheelbase / tan θ exactly as the bus derivation does — 5.10 m of wheelbase at 37.8° of lock, so 6.6 m against the bus’s 7.15 m — and then splits that radius into an inner and an outer wheel angle so both steer tires trace the same centre, which the single-track model on paper does not have to worry about.